3.2 \(\int x^3 \sin ^{-1}(a x) \, dx\)

Optimal. Leaf size=69 \[ -\frac {3 \sin ^{-1}(a x)}{32 a^4}+\frac {x^3 \sqrt {1-a^2 x^2}}{16 a}+\frac {3 x \sqrt {1-a^2 x^2}}{32 a^3}+\frac {1}{4} x^4 \sin ^{-1}(a x) \]

[Out]

-3/32*arcsin(a*x)/a^4+1/4*x^4*arcsin(a*x)+3/32*x*(-a^2*x^2+1)^(1/2)/a^3+1/16*x^3*(-a^2*x^2+1)^(1/2)/a

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Rubi [A]  time = 0.03, antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {4627, 321, 216} \[ \frac {x^3 \sqrt {1-a^2 x^2}}{16 a}+\frac {3 x \sqrt {1-a^2 x^2}}{32 a^3}-\frac {3 \sin ^{-1}(a x)}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x) \]

Antiderivative was successfully verified.

[In]

Int[x^3*ArcSin[a*x],x]

[Out]

(3*x*Sqrt[1 - a^2*x^2])/(32*a^3) + (x^3*Sqrt[1 - a^2*x^2])/(16*a) - (3*ArcSin[a*x])/(32*a^4) + (x^4*ArcSin[a*x
])/4

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 321

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]

Rule 4627

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*ArcSi
n[c*x])^n)/(d*(m + 1)), x] - Dist[(b*c*n)/(d*(m + 1)), Int[((d*x)^(m + 1)*(a + b*ArcSin[c*x])^(n - 1))/Sqrt[1
- c^2*x^2], x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] && NeQ[m, -1]

Rubi steps

\begin {align*} \int x^3 \sin ^{-1}(a x) \, dx &=\frac {1}{4} x^4 \sin ^{-1}(a x)-\frac {1}{4} a \int \frac {x^4}{\sqrt {1-a^2 x^2}} \, dx\\ &=\frac {x^3 \sqrt {1-a^2 x^2}}{16 a}+\frac {1}{4} x^4 \sin ^{-1}(a x)-\frac {3 \int \frac {x^2}{\sqrt {1-a^2 x^2}} \, dx}{16 a}\\ &=\frac {3 x \sqrt {1-a^2 x^2}}{32 a^3}+\frac {x^3 \sqrt {1-a^2 x^2}}{16 a}+\frac {1}{4} x^4 \sin ^{-1}(a x)-\frac {3 \int \frac {1}{\sqrt {1-a^2 x^2}} \, dx}{32 a^3}\\ &=\frac {3 x \sqrt {1-a^2 x^2}}{32 a^3}+\frac {x^3 \sqrt {1-a^2 x^2}}{16 a}-\frac {3 \sin ^{-1}(a x)}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 50, normalized size = 0.72 \[ \frac {\left (8 a^4 x^4-3\right ) \sin ^{-1}(a x)+a x \sqrt {1-a^2 x^2} \left (2 a^2 x^2+3\right )}{32 a^4} \]

Antiderivative was successfully verified.

[In]

Integrate[x^3*ArcSin[a*x],x]

[Out]

(a*x*Sqrt[1 - a^2*x^2]*(3 + 2*a^2*x^2) + (-3 + 8*a^4*x^4)*ArcSin[a*x])/(32*a^4)

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fricas [A]  time = 0.57, size = 47, normalized size = 0.68 \[ \frac {{\left (8 \, a^{4} x^{4} - 3\right )} \arcsin \left (a x\right ) + {\left (2 \, a^{3} x^{3} + 3 \, a x\right )} \sqrt {-a^{2} x^{2} + 1}}{32 \, a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*arcsin(a*x),x, algorithm="fricas")

[Out]

1/32*((8*a^4*x^4 - 3)*arcsin(a*x) + (2*a^3*x^3 + 3*a*x)*sqrt(-a^2*x^2 + 1))/a^4

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giac [A]  time = 0.17, size = 84, normalized size = 1.22 \[ -\frac {{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}} x}{16 \, a^{3}} + \frac {{\left (a^{2} x^{2} - 1\right )}^{2} \arcsin \left (a x\right )}{4 \, a^{4}} + \frac {5 \, \sqrt {-a^{2} x^{2} + 1} x}{32 \, a^{3}} + \frac {{\left (a^{2} x^{2} - 1\right )} \arcsin \left (a x\right )}{2 \, a^{4}} + \frac {5 \, \arcsin \left (a x\right )}{32 \, a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*arcsin(a*x),x, algorithm="giac")

[Out]

-1/16*(-a^2*x^2 + 1)^(3/2)*x/a^3 + 1/4*(a^2*x^2 - 1)^2*arcsin(a*x)/a^4 + 5/32*sqrt(-a^2*x^2 + 1)*x/a^3 + 1/2*(
a^2*x^2 - 1)*arcsin(a*x)/a^4 + 5/32*arcsin(a*x)/a^4

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maple [A]  time = 0.01, size = 60, normalized size = 0.87 \[ \frac {\frac {a^{4} x^{4} \arcsin \left (a x \right )}{4}+\frac {a^{3} x^{3} \sqrt {-a^{2} x^{2}+1}}{16}+\frac {3 a x \sqrt {-a^{2} x^{2}+1}}{32}-\frac {3 \arcsin \left (a x \right )}{32}}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*arcsin(a*x),x)

[Out]

1/a^4*(1/4*a^4*x^4*arcsin(a*x)+1/16*a^3*x^3*(-a^2*x^2+1)^(1/2)+3/32*a*x*(-a^2*x^2+1)^(1/2)-3/32*arcsin(a*x))

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maxima [A]  time = 0.47, size = 61, normalized size = 0.88 \[ \frac {1}{4} \, x^{4} \arcsin \left (a x\right ) + \frac {1}{32} \, {\left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1} x^{3}}{a^{2}} + \frac {3 \, \sqrt {-a^{2} x^{2} + 1} x}{a^{4}} - \frac {3 \, \arcsin \left (a x\right )}{a^{5}}\right )} a \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*arcsin(a*x),x, algorithm="maxima")

[Out]

1/4*x^4*arcsin(a*x) + 1/32*(2*sqrt(-a^2*x^2 + 1)*x^3/a^2 + 3*sqrt(-a^2*x^2 + 1)*x/a^4 - 3*arcsin(a*x)/a^5)*a

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int x^3\,\mathrm {asin}\left (a\,x\right ) \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*asin(a*x),x)

[Out]

int(x^3*asin(a*x), x)

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sympy [A]  time = 0.86, size = 61, normalized size = 0.88 \[ \begin {cases} \frac {x^{4} \operatorname {asin}{\left (a x \right )}}{4} + \frac {x^{3} \sqrt {- a^{2} x^{2} + 1}}{16 a} + \frac {3 x \sqrt {- a^{2} x^{2} + 1}}{32 a^{3}} - \frac {3 \operatorname {asin}{\left (a x \right )}}{32 a^{4}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*asin(a*x),x)

[Out]

Piecewise((x**4*asin(a*x)/4 + x**3*sqrt(-a**2*x**2 + 1)/(16*a) + 3*x*sqrt(-a**2*x**2 + 1)/(32*a**3) - 3*asin(a
*x)/(32*a**4), Ne(a, 0)), (0, True))

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